{"id":671,"date":"2020-01-20T10:35:47","date_gmt":"2020-01-20T13:35:47","guid":{"rendered":"https:\/\/micheladrianomedeiros.com.br\/blog\/?p=671"},"modified":"2020-01-20T10:35:49","modified_gmt":"2020-01-20T13:35:49","slug":"javascript-estrutura-e-algoritmos-de-dados-2","status":"publish","type":"post","link":"https:\/\/micheladrianomedeiros.com.br\/blog\/javascript-estrutura-e-algoritmos-de-dados-2\/","title":{"rendered":"JavaScript Estrutura e Algoritmos de Dados #2"},"content":{"rendered":"\n<p><strong>Regra do Coeficiente:\n\u201cLivre-se das Constantes\u201d<\/strong><\/p>\n\n\n\n<p>Vamos rever a regra do coeficiente.\nEssa regra \u00e9 a mais f\u00e1cil de entender. Simplesmente necessita que voc\u00ea ignore qualquer\ntamanho de entrada de dados das constantes.<\/p>\n\n\n\n<p>Coeficientes no Big-O s\u00e3o insignificantes.\nAl\u00e9m disso, a regra mais importante do Big-O s\u00e3o as nota\u00e7\u00f5es.<\/p>\n\n\n\n<p>Se f(n) \u00e9 O(g(n)), ent\u00e3o kf(n)\n\u00e9 O(g(n)), para qualquer constante k&gt;0.<\/p>\n\n\n\n<p>Isto significa que ambos 5f(n)\ne f(n) tem a mesma nota\u00e7\u00e3o de Big-O de O(f(n)). Um exemplo de c\u00f3digo com a complexidade\nde O(n):<\/p>\n\n\n\n<p>function a(n){<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; var\ncount = 0;<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for(var\ni = 0; i &lt; n; i++){<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; count+=1;<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; }<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; return count;<\/p>\n\n\n\n<p>}<\/p>\n\n\n\n<p>Esse bloco de c\u00f3digo tem f(n)\n= n. Isto adiciona uma contagem de n vezes. Al\u00e9m disso, essa fun\u00e7\u00e3o \u00e9 O(n) de complexidade:<\/p>\n\n\n\n<p>function a(n){<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; var\ncount = 0;<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; for(var\ni = 0; i &lt; 5*n; i++){<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; count+=1;<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; }<\/p>\n\n\n\n<p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; return count;<\/p>\n\n\n\n<p>}<\/p>\n\n\n\n<p>Esse bloco tem f(n) = 5n. Isto\nporque executa do 0 ao 5n. Contudo, os dois exemplos ambos t\u00eam a nota\u00e7\u00e3o Big-O\nde O(n).<\/p>\n\n\n\n<p>Simplesmente, porque se n \u00e9 infinito\nou qualquer outro n\u00famero, as quatros opera\u00e7\u00f5es adicionais s\u00e3o tem significados.<\/p>\n\n\n\n<p>Isto vai ter uma execu\u00e7\u00e3o de n\nvezes. Quaisquer constantes s\u00e3o insignificantes na nota\u00e7\u00e3o Big-O.<\/p>\n\n\n\n<p>O c\u00f3digo a seguir apresenta uma\noutra fun\u00e7\u00e3o com uma complexidade linear com uma opera\u00e7\u00e3o adicional na linha 6.<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"652\" height=\"278\" src=\"https:\/\/micheladrianomedeiros.com.br\/blog\/wp-content\/uploads\/2020\/01\/regradocoeficiente.png\" alt=\"\" class=\"wp-image-672\" srcset=\"https:\/\/micheladrianomedeiros.com.br\/blog\/wp-content\/uploads\/2020\/01\/regradocoeficiente.png 652w, https:\/\/micheladrianomedeiros.com.br\/blog\/wp-content\/uploads\/2020\/01\/regradocoeficiente-300x128.png 300w\" sizes=\"auto, (max-width: 652px) 100vw, 652px\" \/><\/figure><\/div>\n\n\n\n<p>Esse bloco de c\u00f3digo tem f(n)\n= n+1. H\u00e1 um +3 na \u00faltima opera\u00e7\u00e3o (count+=3). Isto ainda tem a nota\u00e7\u00e3o O(n) do\nBig-O.<\/p>\n\n\n\n<p>Isto porque a opera\u00e7\u00e3o + 3 n\u00e3o\ndepende da entrada n. Como n pode ser infinito, ela se torna insignificante.<\/p>\n\n\n\n<p><strong>Regra da Soma: \u201cEleve os\nBig-OS\u201d<\/strong><\/p>\n\n\n\n<p>A regra da soma \u00e9 intuitiva de\nentender, complexidade temporal pode ser adicionada.<\/p>\n\n\n\n<p>Imagine um mestre de algoritmo\nque envolve outros dois algoritmos. A nota\u00e7\u00e3o Big-O deste mestre do algoritmo \u00e9\nsimplesmente a soma das outras duas nota\u00e7\u00f5es Big-O.<\/p>\n\n\n\n<p>Se f(n) \u00e9 O(h(n)) e g(n) \u00e9 O(p(n)),\nent\u00e3o f(n)+g(n) \u00e9 O(h(n)+p(n)).<\/p>\n\n\n\n<p>\u00c9 importante lembrar de\naplicar a regra do coeficiente depois de aplicar esta regra.<\/p>\n\n\n\n<p>Segue um c\u00f3digo que apresenta\numa fun\u00e7\u00e3o com dois loops onde suas complexidades devem ser consideradas\nindependentes e ent\u00e3o somadas:<\/p>\n\n\n\n<div class=\"wp-block-image\"><figure class=\"aligncenter size-large\"><img loading=\"lazy\" decoding=\"async\" width=\"675\" height=\"345\" src=\"https:\/\/micheladrianomedeiros.com.br\/blog\/wp-content\/uploads\/2020\/01\/regradasoma.png\" alt=\"\" class=\"wp-image-673\" srcset=\"https:\/\/micheladrianomedeiros.com.br\/blog\/wp-content\/uploads\/2020\/01\/regradasoma.png 675w, https:\/\/micheladrianomedeiros.com.br\/blog\/wp-content\/uploads\/2020\/01\/regradasoma-300x153.png 300w\" sizes=\"auto, (max-width: 675px) 100vw, 675px\" \/><\/figure><\/div>\n\n\n\n<p>Nesse exemplo, a linha 4 tem\num f(n)=n e na linha 7 tem um f(n)=5n. Isso resulta em 6n.<\/p>\n\n\n\n<p>Contudo, quando aplicada a\nregra do coeficiente, o resultado \u00e9 O(n) = n.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Regra do Coeficiente: \u201cLivre-se das Constantes\u201d Vamos rever a regra do coeficiente. Essa regra \u00e9 a mais f\u00e1cil de entender. Simplesmente necessita que voc\u00ea ignore qualquer tamanho de entrada de dados das constantes. Coeficientes no Big-O s\u00e3o insignificantes. Al\u00e9m disso, a regra mais importante do Big-O s\u00e3o as nota\u00e7\u00f5es. Se f(n) \u00e9 O(g(n)), ent\u00e3o kf(n) [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":374,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[74],"tags":[],"class_list":["post-671","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-javascript"],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v25.5 (Yoast SEO v27.3) - https:\/\/yoast.com\/product\/yoast-seo-premium-wordpress\/ -->\n<title>JavaScript Estrutura e Algoritmos de Dados #2 - Viciados em Aprender<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/micheladrianomedeiros.com.br\/blog\/javascript-estrutura-e-algoritmos-de-dados-2\/\" \/>\n<meta property=\"og:locale\" content=\"pt_PT\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"JavaScript Estrutura e Algoritmos de Dados #2\" \/>\n<meta property=\"og:description\" content=\"Regra do Coeficiente: \u201cLivre-se das Constantes\u201d Vamos rever a regra do coeficiente. 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Essa regra \u00e9 a mais f\u00e1cil de entender. Simplesmente necessita que voc\u00ea ignore qualquer tamanho de entrada de dados das constantes. Coeficientes no Big-O s\u00e3o insignificantes. Al\u00e9m disso, a regra mais importante do Big-O s\u00e3o as nota\u00e7\u00f5es. 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